//情况一：
letarr0 = [1,1,1,0,5,6];
uniqueify(arr0);
//输出：[1,0,5,6]

//情况二：
letarr1 = [
    {id: 1, name:'xx'},
    {id: 1, name:'xx'},
    {id: 2, name:'xx'},
    {id: 1, name:'xx'},
    {id: 1, name:'xx'}
];
uniqueify(arr1, a=>a.id);//假如这里的去重规则依据为id
//输出：
[
    {id: 1, name:'xx'},
    {id: 2, name:'xx'}
];

//情况三：
letarr2 = [
    {name:'xx',sex:'male'},
    {name:'xx',sex:'female'},
    {name:'xx',sex:'male'},
    {name:'aa',sex:'male'},
    {name:'aa',sex:'male'}
];
uniqueify(arr2, a=>(a.name+a.sex));//假如这里的去重规则依据为名字和性别均相同，才算是相同
//输出：
[
    {name:'xx',sex:'male'},
    {name:'xx',sex:'female'},
    {name:'aa',sex:'male'}
];