如下语句块

string1[] = “programmer";

string2[] = “languager";

char *str1 = string1;

char *str2 = string2;

int i;

for(i =0 ;i < 7;i++)

{

   if(*(string1 + i) ==  *(string2 + i) )

  {

     printf("%c",*(string1 + i));

  }

}

输出结果为[$##$]